# Solving problems in electrical engineering – Voltage divider

The scheme of the resistance** voltage divider:**

(1)

Simple **resistance-voltage divider** consists of two series-connected resistors R_{1} and R_{2}, connected to the voltage source U.
Since the resistors are connected in series, the current through them will be the same according to the first Kirchhoff’s law.
The voltage drop (potential drop at the flow of the charge from one point to another point of the circuit) on each resistor according to the Ohm’s
law is proportional to the resistance (the current, as stated earlier, is the same):

U=I·R;

For each resistor:

U_{1}=I·R_{1}

U_{2}=I·R_{2}

Having divided the expression for U_{1} by the expression for U_{2} we receive:

U_{1}/U_{2}=R_{1}/R_{2};

Thus, the ratio of voltages U_{1} и U_{2} are exactly equal to the ratio of resistances R_{1} и R_{2}.

Using the equality:

U=U_{1}+U_{2}

We receive the formula connecting output (U_{2}) and input (U) voltage divider:

U_{2}=U·R_{2}/(R_{2}+R_{1})

It should be noted that the load impedance of the **voltage divider** should be much more than own resistance of the divider, so that in calculations this resistance
which is parallel to R_{2} can be neglected.
To select specific resistances values in practice is usually enough to follow the following algorithm.
First it is necessary to define the value of the current divider working without load.
This current should be significantly more than current (usually accept excess from 10 times in size) consumed by the load, but, however,
specified current should not create surcharge on the voltage source.
Based on the current value, we define the value of the overall resistance according to the Ohm’s law R=R_{1}+R_{2}.
It is necessary only to take exact values of resistances from the standard series which ratio values are close to the desired voltages ratio and the amount of values is
close to the calculated amount. At calculating of the real divider it is necessary to take into account the temperature coefficient of the resistance,
tolerance on nominal resistance values, variation range of the input voltage and possible properties changes of the load divider, as well as the maximum dissipated power of resistors –
it should exceed the power emitted on them P=I^{2}·(R_{1}+R_{2}), where I – current source without load (in this case the maximum current flows through resistors).