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Theoretical foundations of electrical engineering

# Calculation of the magnetic circuit, Weber-Ampere characteristics

Given
W1=400;
W2=500;
W3=1000;
Steel: E11;
l=24 cm;
S=8 cm2;
F1=2000 A;
F2=1000 A;
F3=0 A;
δ3=1 mm;
δ12=0 mm;
l1=1,5l;
l2=l;
l3=2l;
S1=S3=S;
S2=1,5S.

Find
Magnetic flux in branches: Φ1, Φ2, Φ3 — ?

## Solution

We set the value of the magnetic inductance 0,5 T in the second branch. Then:

According to the magnetizing curve:
H=H2=f(Φ2)=1,7 A/cm;
Field intensity in the air gap:

Magnetic voltages on the resistances gap:

According to the second Kirchhoff's law for magnetic circuits we write down the system of equations and solve it:

We make the same actions for other values of the magnetic inductance (the calculation is computerized in Excel)

According to the specified table of values we make Weber-Ampere characteristics of the circuit:

The diagram shows that fluxes are equal:

Ответ:

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